I feel you dissolved 220g of NaClO3 in 100g of 60c water , how much NaClO3 would be settled on the bottom. Show work. Please explain how the solubility of NaClO3 at 60 in water is 137g, where does the 137 grams comes from?
Concentration:
m = 220 g of NaClO3 in m = 100 g
Solubility
m = 137 g of NaClO3 in m = 100 g
therefore
220-137 = 83 g of NaClO3 will not be soluble
this will go directly to the bottom as solids
note that 137 g are typically experimenta data
You can get this via:
Sample of water = 100 g
T = 0,5,10....30...50...60°C
at T = 60°C
addition of NaClO3 --> 137 g will be soluble, that is, 137 g dissapear in solution of 100 g of water
then, you can assume this is constant since solubility won0t change if T is constant
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