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An adsorbent is exposed to a mixture of 0.5 bar nitrogen and 1.5 bar oxygen. If...

An adsorbent is exposed to a mixture of 0.5 bar nitrogen and 1.5 bar oxygen. If the surface coverages of both adsorbates are the same, what can you state about KA and KB?

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Answer #1

Adsorption is a reversible process which can be given as

O2(g) + M(surface) MO2 KB = rate constant of adsorption of O2

N2 + M(surface)   MN2.   KA=rate constant of adsorption of N2

we know tha adsorption is directly proortiona to pressure, adsorption increases with increase in pressure

Nitrogen with small pressure that is 0.5 bar occupies half of the adsorption sites shows that its KA value is higher and it is easily liquifable gas

Oxygen with high pressure that is 1.5 bar occupies half of the adsorption sites shows that its KB value is lower and it is not easily liquifable gas .

Smaller adsorption constant high pressure is required for adsorption to take place

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