Here are two possible reactions. Which one is correct and why is the other one incorrect?
Mn2+(aq) + 2HClO(aq) -----> MnO2(s) + 2Cl-(aq) + 2H+(aq)
Mn2+(aq) + HClO(aq) + H2O(l) -----> MnO2(s) + Cl-(aq) + 3H+(aq)
There are plenty of ways to solve this... mass balance, energy balance, electorn balance, electrode potentials, free gibbs energy, entropy, etc...
The easiest way is doing an electron chage balance:
Mn2+(aq) + 2HClO(aq) -----> MnO2(s) + 2Cl-(aq) + 2H+(aq)
Charge on the left = +2 +2*0 = +2
Charge on the right = 0+2*(-1) + 2*(1) =-2+2 = 0
There is no balance since lft side is +2 charged and right side is neutrally, 0, charged
For the second equation
Mn2+(aq) + HClO(aq) + H2O(l) -----> MnO2(s) + Cl-(aq) + 3H+(aq)
Charge on the left = +2 +2*0+ 0 = +2
Charge on the right = 0+(-1) + 3*(1) = -1+3 = +2
Both sides are +2 charged, therefore, it is possible to do trhis (there is an electron balance)
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