CHEMISTRY QUESTION Calculate the standard reduction potential for the reaction between Pb2+ and Zn(s). The units are volts and be sure to include a minus sign if needed.
anode reaction: oxidation takes place
Zn(s) -------------------------> Zn+2 (aq) + 2e- , E0Zn+2/Zn = - 0.76 V
cathode reaction : reduction takes palce
Pb+2(aq) + 2e- -----------------------------> Pb(s) , E0Pb+2/Pb = -0.13V
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net reaction: Zn(s) +Pb+2(aq) -------------------------> Zn+2 (aq) + Pb(s)
E0cell= E0cathode- E0anode
E0cell= E0Pb+2/Pb - E0Zn+2/Zn
= -0.13 - (-0.76)
= 0.63 V
standard reduction potential = 0.63 V
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