Calculate the cell potential for the following reaction as written at 25.00 °C, given that [Zn 2 ] = 0.768 M and [Sn2 ] = 0.0200 M. Standard reduction potentials can be found here. Zn(s)+Sn2+(aq)----->Zn2+(aq)+Sn(s)
Zn+2e- ---->Zn = -0.76
Sn+ + 2e- ----> Sn = -0.14
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