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Lithium and nitrogen react to produce lithium nitride, in the following equation: Li(s) + N2(g) à...

Lithium and nitrogen react to produce lithium nitride, in the following equation: Li(s) + N2(g) à Li3N(s) How many moles of lithium nitride are produced when 2.760 mol of elemental nitrogen completely reacts in this fashion?

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Answer #1

6 Li (s) +   N2 (g) ----------------> 2 Li3N (s)

6 mol        1 mol                             2 mol

                 2.760 mol                        ??

1mol N2   --------------> 2 mol Li3N

2.760 mol N2 -------------->   ??

moles of lithium nitride are produced = 2.760x 2 / 1

moles of lithium nitride are produced = 5.520 mol Li3N

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