Question

Lithium nitride reacts with water to produce ammonia and lithium hydroxide according to the equation, Li3N+3H20-->NH+3LiOH

Heavy water is water with the isotope deuterium in place of ordinary hydrogen, and its formula is D2O. The above reaction can be used to produce heavy ammonia, ND3(g), according to the equation, Li3N+3D2O-->ND3+3LiOD
Calculate how many grams of heavy water are required to produce 480.0 mg of ND3(g). The mass of deuterium, D, is 2.014 g/mol.

Answer 1

Li3N + 3D2O --> ND3 + 3LiOD

from this reaction it is clear that

forom this balanced equation it is clear that fo r1 mole of ND3 3 moles of D2O required

first calculate th emoles of ND3 = weight of ND3 in grams / molar mass of ND3

= 0.48 g / 20.05 g/mol

= 0.024 moles

according to balanced equation

0.024 moles of ND3 required 3 x 0.024 moles of D2O = 0.072 moles

weight of D2O = moles of D2O x molar mass of D2O

= 0.072 mole x 2.014 g/mole

= 0.145 grams of D2O required or

= 145.0 grams of D2O required