When you add 0.05 ml of 0.50M sodium thiosulfateNa2SO2O3 to 2.0 ml if 0.10M silvernitrate, a precipitate of Ag2S2O3 formed byequation 2Ag+ +S2O3-2 <------->Ag2(S2O3) (s) Assume that this reaction goes 100% to completion. a) Set up a reaction table and calculate the [Ag+] afterreaction b) Calculate the value of Ecell expected using Ag|([Ag+] from a) asthe test half-cell, and Ag+(1.0M)|Ag as the referencehalf-cell.
I don't have money to see answer, just a young man trying to succeed and save lives.
The final concentration for each ion is:
From the reaction:
2Ag+ | S2O32- | ----> | Ag2(S2O3) | |
initial | 0.098 | 0.012 | 0 | |
after reaction | 0.098-2*(0.012) | 0.012-0.012 | 0.012 |
From the table you can see all S2O3 is going to be consumed
So the final concentration is 0.098-2*(0.012)=0.074M
b)
For the second, I do not understand what cell is it talking about, but you can calculate the potential of the half cell asuming Ag+ reduces to Ag
, since the standard potentials are calculated at 1M concentrations, Eo is the reference potential.
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