Question

When 230 mg of AgNO₃ and 0.02 g of Kl are mixed together in 1 L of water, how much Agl will form?

Answer 1

first write the balanced equation

AgNO3 + KI ---> AgI + KNO3

230 mg = 0.23 grams

no o fmoles of AgNO3 = 0.23 g / 169.87 g/mol = 0.001354 moles

no of moles of KI = 0.02 g / 166 g/mol = 0.0001205 moles

actually to get one mole of AgI both will required eqially one on mole

but here KI is limiting agent

so product will form according to limiting agent

0.0001205 moles of AgI will form

weight of AgI = moles of AgI x molar mass of AgI

= 0.0001205 moles x 234.8 g/mol

= 0.0283 grams AgI will form