Here we have given the concentration of ethyl alcohol 0.065 M,
i.e we know the molarity , from that we can calculate the moles of ethanol present in 5.6 L volume of blood and from moles we can calculate the grams of ethyl alcohol .
Molarity= moles/volume in L,
0.065 =MOLES/5.6 L,
MOLES=0.065*5.6 L,
MOLES=0.364 (MOLES OF ETHYL ALCOHOL),
NOW we can calculate the grams of alcohol present in 5.6 L blood volume.
mass= moles* mol. wt,
mass = 0.364* 46.06,
mass= 16.76 grams of ethyl alcohol
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