A) Select all the processes below that are SPONTANEOUS.
Freezing of water at 10°C |
||
Corrosion of iron metal (rust) |
||
Expansion of gas to fill the available volume |
||
Boiling of gasoline at 25°C and 1 atm pressure |
B) What is the Q (IP) when 287 mL of 0.068 M solution of Na2CO3(aq) are mixed with 211 mL of 0.075 M solution of BaCl2(aq). The solid product is BaCO3. Express your answer in scientific notation.
A) Corrosion of iron metal (rust), Expansion of gas to fill the available volume
B) Na2CO3 (aq) + BaCl2 (aq) -----> 2 NaCl (aq) + BaCO3 (s)
Moles of Na2CO3 = 0.068*287 = 19.516 millimoles
Moles of BaCl2 = 211*0.075 = 15.825 millimoles
So, BaCl2 is limiting reagent
Therefore, 15.825 milllimoles of BaCO3 (ppt) is formed
BaCO3 ==== Ba2+ + CO3 2-
ionic product = [Ba2+] [CO3 2-] = (15.825/498) * (15.825/498) = 1.01*10^-3 (as total volume = 211+287 =498 ml)
Get Answers For Free
Most questions answered within 1 hours.