Question

△H=mCh2o(Ti-Tf) this is my result from lab experiment, how to get the heat change.. please explain...

△H=mCh2o(Ti-Tf)

this is my result from lab experiment, how to get the heat change.. please explain this.

Mg ribbon

Vacid

M mg

Ti

Tf

100 mL

.11g

22.5 C

27.8 C

MgO

Vacid

M mgO

Ti

Tf

100 mL

.8 g

22.4 C

26.7 C
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Answer #1

Solution:

C value of water is 4.186 J/gm C, Ti = 22.5 C, Tf = 27.8 C { as MgO oxidizes to give Mg the values of Mg is taken for calculating the heat change in forward direction}

Mass is calculated as Mg reduced from MgO so m = (0.11-0.8) g = 0.3 g

by substituting all the values in the equation we get,

q = (0.3) (4.186) (27.8 - 22.5)

q = 66.5574 J

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