The half-equivalence point of a titration occurs half way to the end point, where half of the analyte has reacted to form its conjugate, and the other half still remains unreacted. If 0.540 moles of a monoprotic weak acid (Ka = 7.2 × 10-5) is titrated with NaOH, what is the pH of the solution at the half-equivalence point
(answer is not 4.65)
HA-----> H+ + A-
initial 0.54 0 0
change -x +x +x
at equilibrium 0.54-x +x +x
Ka = [H+][A-]/[HA]
7.2*10-5 = x*x/0.54-x
3.88*10-5 -7.2*10-5 x =x2
x2 +7.2*10-5 x-3.88*10-5 =0
x = 0.0061M
[H+] = 0.0061M
PH = -log[H+]
= -log0.0061
PH = 2.214 >>> answer
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