balance the following equation in acidic conditions. phases are optional
H_3AsO_3 + I_3 ---> H_3AsO_4 + I^-1
H3AsO3 + I3 = H3AsO4 + I-
Split
H3AsO3 --> H3AsO4
I3 = I-
balance elements
H3AsO3 --> H3AsO4
I3 = 3I-
balnce O adding H2O
H2O + H3AsO3 --> H3AsO4
I3 = 3I-
blaance H adding H+
H2O + H3AsO3 --> H3AsO4 +2H+
I3 = 3I-
balance charges
H2O + H3AsO3 --> H3AsO4 +2H+ +2e-
3e- + I3 = 3I-
Balance E
3H2O + 3H3AsO3 --> 3H3AsO4 +6H+ +6e-
6e- + 2I3 = 6I-
add both
3H2O + 3H3AsO3 + 6e- + 2I3--> 3H3AsO4 +6H+ +6e- + 6I-
cancel common terms
3H2O + 3H3AsO3 + 2I3--> 3H3AsO4 +6H+ 6I-
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