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what is the empirical formula of an oxide of nitrogen that contains 63.64% nitrogen by mass?

what is the empirical formula of an oxide of nitrogen that contains 63.64% nitrogen by mass?

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Answer #1

molar mass of N = 14 g/mol

molar mass of O = 16 g/mol

moles of N = 63.64 / 14 = 4.55

moles of O = 36.36 / 16 = 2.27

N             O

4.55                     2.27

2                             1

the emperical formula = N2O

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