A power plant burns 150 U.S. short tons of coal per day, and there are 18.2 lb. of flue gas produced per pound of coal. The sulfur content of the coal is 2.0 percent and the molar mass (molecular weight) of the flue gas is 30.5. If all the sulfur in the coal appears as SO2 in the flue gas, what is the concentration of SO2 in the flue gas in parts per million?
first we will convert ton to pound
150 tons = 300000 pounds, per pound of coal produce 18.2 lb
1 pound=18.2 lb therefore, 300000 pounds = how many?
first we wiill convert lb to kgs
18.2 lb= 8.2553 kg
1 pound= 8.2553 kg
300000=?
=300000*8.2553=2476590/1=2476590 KGS
2476590/30.5 (MOLAR MASS OF GAS)=81199.6 MOLES
2479590*2=4953180/100=49531.8 Sulpher prsent
49531.8/32=1547.86 moles (S)
therefore 1 mole (S) = 1 mole SO2, 1547.86*64=99063.6 kGS
99063.6/Total wt of flue gas,99063.6/2479590=0.04*100=4 percent SO2
1 % =10000 PPM, Therefore, 4% =40000 ppm concentration of SO2 PRESENT
Get Answers For Free
Most questions answered within 1 hours.