Question

Show using chemical equations how successive deprotonation of (Cu(OH₂)₂(NH₃)₂)²⁺ produces an oxoacid

Answer 1

First I think the complex has to be an octahedral one so no of NH3 ligands has to be 4 not 2.(Cu(OH2)2(NH3)4)2+

According to the question given,deprotonation occurs as follows.

Deprotonation is caused by the high charge density on the central action which weakens the O-H bonds in water (H2O) ligands and enables the H+ to leave.

According to that,the complex is dark blue in colour

(Cu(OH2)2(NH3)2)2+ + OH- (Cu(OH2)(OH)(NH3)2)+ +H2O

Further deprotonation gives,

(Cu(OH2)(NH3)2) + 2H2O