Question

The Extracellular conectration of a chloride ion is 131 mmol/L. The equilibirum concentration is -68.8 mV....

The Extracellular conectration of a chloride ion is 131 mmol/L. The equilibirum concentration is -68.8 mV. Using the Nernst equation calculate the intracellular concentration.

E = RT/zF * ln ( Xout - Xin )

R= 8.314
T= 298 K
z = 1
F = 96487

I know that the answer is 9 mmol/L I just can't work the problem out myself. It would be helpful to see how one would solve for intracellular concentration variable first.

Homework Answers

Answer #1

The Extracellular conectration of a chloride ion is 131 mmol/L. The equilibirum concentration is -68.8 mV. Using the Nernst equation calculate the intracellular concentration.

E = RT/zF * ln ( Xout - Xin )

R= 8.314

T= 298 K

z = 1

F = 96487

I know that the answer is 9 mmol/L I just can't work the problem out myself. It would be helpful to see how one would solve for intracellular concentration variable first.

Substituting values in above equation,

-68.8×10-3 = [8.314×298/(-1)× 96487] × ln(131/Xin)

-68.8×10-3 = -0.0256 × ln(131/Xin)

ln(131/Xin) = 2687.5×10-3

ln(131/Xin) =2.687

Xin = 8.919 mMol/L

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