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what is the molality for13.7g of sucrose in 668g of water

what is the molality for13.7g of sucrose in 668g of water

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Answer #1

sucrose molar mass = 342 g /mol

sucrose moles = 13.7 / 342

                         = 0.04

mass of solvent water = 668 g = 0.668 kg

molality = moles of solute / mass of solvent (kg)

              = 0.04 / 0.668

             = 0.05997 m

              = 0.060 m

molality = 0.060 m

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