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The calcium ion selective electrode (ISE) measures 11.8 mV in a 1 mM Ca2+ solution at...

The calcium ion selective electrode (ISE) measures 11.8 mV in a 1 mM Ca2+ solution at room temperature. Then the ISE is placed in another solution at body temperature and it measures 20 mV. What is the calcium concentration of the new solution? To avoid complicated theory assume that Eo is not Temperature dependent.

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Answer #1

For Calcium REDOX equation is:

Ca+2 + 2e- <======> Cao

With first dates will calculate Eo for calcium ion selective electrode, using follow equation (Nernst Equation)

conventionally Ccao=1

E=11,8mV=11,8.10-3V

R=gases constant 8,314J/k.mol

n= mol of electrons involved =2 according to redox reaction

F= faraday constant 96500J/V.mol

T=Temperature

...Replacing first dates in equation for calculate Eo

Eo for calcium ion selective electrode is 0,100V.

Calculating calcium concentration of the new solution.

Solve Cca+2 of the nernst equation:

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