Question

The equilibrium constant of a reaction is 2.61e+02 at 342 K and 5.99e+03 at 436 K....

The equilibrium constant of a reaction is 2.61e+02 at 342 K and 5.99e+03 at 436 K. Determine the following for this reaction: Ho= kJ/mol So= J/mol-K

What is the value of the equilibrium constant at 389 K?

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