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The standard enthalpy of propane (C3H8) is -103.8 kJ/mol. Find the gross and net heat released...

The standard enthalpy of propane (C3H8) is -103.8 kJ/mol. Find the gross and net heat released when 1 kg of propane is burned.

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Answer #1

C3H8 + 5O2 -----> 3CO2 + 4H2O

H = Hproducts-Hreactants

     = 3HCo2 + 4H H2O - HC3H8

    = 3*-393.5 + 4*-285.3 -(-103.8)

= -1180.5 -1141.2 +103.8   = -2217.9kj

1 mole of propane combustion to gives -2217.9Kj

44gm of C3H8 combution to gives - 2217.9 kj

1000gm of C3H8 combution to gives = -2217.9*1000/44 = 50406.8 KJ

    

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