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Construct a Al-Br2 electrochemical cell, write down the anode reaction and cathode reaction and determine the...

Construct a Al-Br2 electrochemical cell, write down the anode reaction and cathode reaction and determine the cell voltage.

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Answer #1

Ande reaction :

Oxidation half reaction :

Al (s) ------------------> Al+3 + 3 e-                        Eo = - 1.662 V

cathode reaction :

reduction half reaction ;

Br2 + 2e-   ---------------> 2 Br -                   Eo = 1.0873 V

Overall reaction :

3 Br2 + 2 Al   --------------> 2 Al+3 + 6 Br -

Eo cell = Eo cathode - Eo anode

            = 1.0873 - (- 1.662)

            = 2.75 V

cell voltage.= 2.75 V

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