A buffer contains equal concentrations of a weak base, B, and its conjugate acid, BH+. If the value of Kb for B is 1.0 x 10-9, what is the pH of the buffer?
A. 13.0
B. 9.0
C. 1.0
D. 7.0
E. 5.0
Please show your work. Thank you.
Use Handerson's equation to determine the pOH of the given weak base.
pOH = pKb + log [salt]/[base]
Given Kb = 1.0 x 10-9
pKb = -log(1.0 x 10-9)
=9.0
Let the concentration of weak base B and its conjugate acid BH+ = 10M
pOH = 9.0+log[10/10]
=>pOH = 9.0
We know that pH+pOH =14
pOH = 9.0
Then pH = 14.0-9.0
= 5.0
Hence, optionE is the correct answer.
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