To the nearest tenths, what is the value of ΔG°′ (in kcal/mol) for the overall spontaneous reaction that would result given the following two half reactions?
Aox + 2H+ + 2e- → Ared E°′ = -0.3
Box + 2H+ + 2e- → Bred E°′ = -0.18
for spontaneous reaction Eocell should be positive and ΔG° should be negative
to get Eocell psotive
Eocell = higher potential - lower potential
= -0.18 + 0.3
= 0.12 V
ΔG° = - n F Eo
= -2 x 96500 x 0.12 x 10^-3
= - 23.2 kJ / mol (divide by 4.184 to convert into calories)
= -5.5 kcal / mol
ΔG° = - 5.5 kcal / mol
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