Question

What mass of propane, C3H8 must be burned in order to produce 76,000 kJ of energy? C3H8 + 5O2 → 3CO2 + 4H2O ∆H = -2200 kJ

Answer 1

C3H8 + 5   O2 ----------------->    3 CO2 + 4   H2O                 ∆H = -2200 kJ

for 1 mol C3H8   ------------>   - 2200 kJ energy produced.

for    ??              ------------->   76,000 kJ

number of moles of propane = 76,000 / 2200

                                              = 34.54 mol

mass of propane = 34.54 x 44.0956 = 1523.3 g

mass of propane = 1523 g