Question

Calculate the value of pFe2+ at the equivalence point for the titation of 2.0mmol of Fe2+...

Calculate the value of pFe2+ at the equivalence point for the titation of 2.0mmol of Fe2+ with EDTA at pH 4.00. The final volume is 100mL. Keff=7.6*105.

Science   Chemistry   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Calculate the pH at the equivalence point for the following titration: 0.1 M HCl and 0.1...
Calculate the pH at the equivalence point for the following titration: 0.1 M HCl and 0.1 M NH3 The finale answer should be 5.28 And there is no volume
A 100ml solution of 0.50M acetic acid (Ka=1.78x10^-5) is titrated to equivalence point with 100ml of...
A 100ml solution of 0.50M acetic acid (Ka=1.78x10^-5) is titrated to equivalence point with 100ml of 0.50M NaOH what is the Ph of the resulting solution
Calculate the pH at the equivalence point in the titration of the weak base, B, having...
Calculate the pH at the equivalence point in the titration of the weak base, B, having a Kb of 1.00 x 10−8 when the initial formal concentration of the B titrand is 0.01000F and its initial volume is 0.1000 L. The titrant is standardized HCl with a concentration of 0.1000 M.
1. A 100.00 mL solution of 0.0500 M Cu2+ was buffered to pH 9.00 and titrated...
1. A 100.00 mL solution of 0.0500 M Cu2+ was buffered to pH 9.00 and titrated with 0.0650 M EDTA ( a) What volume of EDTA is needed to reach the equivalence point? (b) If the conditional formation constant for the Cu-EDTA complex at pH = 9.00 is K’f = 2.47 x 1017, calculate the [Cu2+] at the equivalence point.  
Calculate the pH at the equivalence point for the titration of 0.180 M methylamine (CH3NH2) with...
Calculate the pH at the equivalence point for the titration of 0.180 M methylamine (CH3NH2) with 0.180 M HCl. The Kb of methylamine is 5.0× 10–4. pH=?
The pH = pKa at equivalence point a) at half the volume of base needed to...
The pH = pKa at equivalence point a) at half the volume of base needed to reach equivalence point b) when all of the acid is neutralized c) plus or minus one pH unit from equivalence d) none of the above Please also EXPLAIN your asnwer!
Calculate the pH at the equivalence point when you titrate 1.6M of CH_3NH_2 and 1.6M of...
Calculate the pH at the equivalence point when you titrate 1.6M of CH_3NH_2 and 1.6M of HCl.
Calculate the pH at the equivalence point for the titration of .100M methylamine (CH3NH2) with .100...
Calculate the pH at the equivalence point for the titration of .100M methylamine (CH3NH2) with .100 M HCL. The Kb of methylamine is 5.0x10^-4
Calculate the pH at the equivalence point for the titration of 0.130 M methylamine (CH3NH2) with...
Calculate the pH at the equivalence point for the titration of 0.130 M methylamine (CH3NH2) with 0.130 M HCl. The Kb of methylamine is 5.0× 10–4.
Calculate the pH at the equivalence point in the titration of 50.0 mL of 0.125 M...
Calculate the pH at the equivalence point in the titration of 50.0 mL of 0.125 M methylamine (Kb = 4.4 × 10−4) with 0.265 M HCl..
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT