A laboratory requires at least 0.92 mg of a chemical X in order to achieve acceptable laboratory accuracy. Assuming that chemical X has a MW of 178 and the anticipated ppm value is between 50 and 150 ppm. What is the minimum volume of air which must be collected with a pump set at 1 L/min
The required mass of chemical X is = 0.92mg = 0.00092 gm
molar mass of chemical X is = 178gm
number of required moles is given by
a) If air concentration is 50 ppm that is
50ppm = 50mg/L = 0.05gm
number of moles of chemical X in one litre of air is given by
now
minimum volume of air needed to be collected is given by
If 1litre of air consists of 2.8X10-4mol of chemical X
then
volume of air consisting 0.51 X 10-5 mol is =
b) if air concentration is 150 ppm then
150ppm = 150 mg/l = 0.15gm
number moles of chemical X in 1Litre is given by
hence if one litre of air possess 8.42X10-4 mol then
volume of air required to be taken for 0.51X10-5 mol is given by
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