Question

1a. How many moles of carbon monoxide are required to react completely with 3.38 L of oxygen gas according to the following reaction at 0°C and 1 atm? carbon monoxide (g) + oxygen(g)carbon dioxide (g) ____________ moles carbon monoxide?

1b. What volume of hydrogen gas is required to react completely with 1.21 mol of nitrogen gas according to the following reaction at 0°C and 1 atm? nitrogen (g) + hydrogen(g)ammonia (g) ______________liters hydrogen gas?

Answer 1

Lets write the reaction equation first:

2CO(g) + O₂(g) ----->2CO₂(g)

moles can be obtained using ideal gas equation

PV = nRT

n = PV/RT = 1 atm x 3.38L / (0.08206 atm.L/mol.K x 273K) = 0.151 mol

moles of oxygen gas = 0.151 mol

1 mol oxygen needs 2 moles CO to react completely

0.151 mol oxygen will need = 2 x 0.151 mol CO = 0.302 moles

b)

N₂(g) +3H₂(g) ----> 2NH₃(g)

1 mole nitrogen needs 3 mol hydrogen to react completly

1.21 mol will need = 1.21 x 3 = 3.63 moles hydrogen

volume = V = nRT/P = 3.63 moles x 0.08206 atm.L/mol.K x 273K / 1atm = 81.32 L