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You are titrating 100.0 mL of 0.0200 M Fe3+ in 1 M HClO4 with a titrant...

You are titrating 100.0 mL of 0.0200 M Fe3+ in 1 M HClO4 with a titrant solution of 0.100 M Cu+ to give Fe2+ and Cu2+ (E0 Cu2+/Cu+= 0.161V; E0 Fe3+/Fe2+= 0.767V).

What is the cell potential after pouring 10.0mL of titrant?

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Answer #1

Applying Nernst equation:

Ecell = Eocell - (0.0591/n)logQ

= 0.606 - (0.0591/1)log(0.0091)

= 0.485 V

So, answer is 0.485 V

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