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A solution containing a mixture of metal cations was treated with dilute HCl and no precipitate...

A solution containing a mixture of metal cations was treated with dilute HCl and no precipitate formed. Next, H2S was bubbled through the acidic solution. A precipitate formed and was filtered off. Then, the pH was raised to about 8 and H2S was again bubbled through the solution. A precipitate again formed and was filtered off. Finally, the solution was treated with a sodium carbonate solution, which resulted in no precipitation. Which metal ions were definitely present, which were definitely absent, and which may or may not have been present in the orginal mixture? Which are possibly present and which are definitely absent? Sn^4+ Mn^2+ Cu^2+ Ni^2+ Ca^2+

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Answer #1

Among the given cations Cu2+, Sn4+ belongs to II group actions (reagent: dil. HCl and dil. H2S). Ni2+, Mn2+ belongs to IV group cations(reagent: NH4Cl, NH4OH and H2S). Ca2+ belongs to V group cations(reagent: Na2CO3). A precipitate is formed when H2S gas is bubbled through the solution. The solution definitely contains II group cations Cu2+ and Sn4+. A precipitate is formed upon bubbling of H2S gas through the solution in basic conditions. Therefore, the given solution definitely contains IV group actions Ni2+ and Mn2+. No precipitate is formed upon the addition Of Na2CO3, so V group cations, Ca2+ is absent

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