How does [B] change when D is added to the following reaction at
equilibrium?
2 A(g) + B(g) ↔ 2 C(g) + D(s)
How does [B] change when D is added to the following reaction at
equilibrium?
2 A(g) + B(g) ↔ 2 C(g) + D(s)
[B] will not change. | |
Cannot be predicted. | |
[B] will increase. | |
[B] will decrease. |
According to the Le-Charterlier's principle,If the concentration of reactants is increased or product is removed , the reaction will take place in the forward direction.
If the concentration of products is increased or reactants is removed , the reaction will take place in the backward direction.
2 A(g) + B(g) ↔ 2 C(g) + D(s)
By addition of D( which is a product) the concentration of product is increasing so the backward reaction takes place so that the concentration of B increases.
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