Question

How would I calculate the rate of reaction per each 1 minute time interval as it prgresses to completion (data shown in the table below)?

Time(min)	Trial 1 (O.D)	Trial 2 (O.D)	Mean (O.D)
0	0.032	0.053	0.0425
1	0.249	0.807	0.528
2	0.465	1.223	0.844
3	0.703	1.401	1.052
4	0.929	1.455	1.192
5	1.087	1.472	1.2795
6	1.256	1.475	1.3655
7	1.354	1.481	1.4175
8	1.404	1.481	1.4425
9	1.464	1.482	1.473
10	1.484	1.482	1.483

Answer 1

The progress of a simple reaction so, rate equation will be

rate = Δ[A] / Δt

so we can find easily rate of each 1 minutes interval

rate 1 = [ 0.528 - 0.0425 ] / [1 - 0 ] = 0.4855 Min^-1

similarly for all 1 minutes interval

rate 2 = [0.844 - 0.528 ] / [ 2 - 1 ] = 0.316 M^-1

rate 3 = [ 1.052 - 0.844 ] / [3-2] = 0.208 M^-1

rate 4 = [ 1.192 - 1.052 ] / [4-3] = 0.140 M^-1

rate 5 = [ 1.2795 - 1.192 ] / [5-4] = 0.0875 M^-1

rate 6 = [1.3655 - 1.2795 ] / [ 6-5] = 0.0860 M^-1

rate 7 = [1.4175 - 1.3655 ] / [7-6] = 0.0520 M^-1

rate 8 = [1.4425 - 1.4175] / [8-7] = 0.0250 M^-1

rate 9 = [1.473 - 1.4425 ] / [9-8] = 0.035 M^-1

rate 10 = [1.482 - 1.473 ] / [10-9] = 0.009 M^-1

answered by: anonymous