Question

how much sulfuric acid ( 98.0% by weight) is needed in the preparation of 250 grams of 25.0% solution of the acid by weight ? how would you actually prepare the solution?

Answer 1

98% solution equivalent to 10 M solution

needed 25% seta equivalent to (2.55 )

I think one should take 63.75ml of the 98% sulfuric acid and dilute it to 250 ml to get the final desire 250 mL of 25.0% solution.                Preparation of H2SO4 solution you have to take care because so much heat will generate. so 250-63.75= 186.25 ml water. 63.75 ml H2SO4 should add dropwise to the 186.25 ml water                                                                                                                                     

eai hisebe jodi 63.75mL 98% solution ke dilute kori 250 ml e then amara 25% 250 ml solution pabo