Question

Organic chemistry

For permanganate test, you will use solution of KMnO4 in sulfuric acid. How much of KMnO4 (in g) and how much of sulfuric acid (in mL) you would have to take to prepare 100 mL solution in which concentrations of KMnO4 is 0.5 M and concentrations of H2SO4 is 1 M. Concentration of commercially available sulfuric acid is 18 M.

Answer 1

MW of KMnO4 = 158.034 g/mol

V total = 100 ml

then

first, get the sulfuric acid to 1 M

M1*V1 = M2V2

V1 = M2V2/M1 = 1/18*100 = 5.5555 ml of concnetrated 18 M H2SO4 acid is needed

then

add 50 ml of water; mix

then add

M = 0.5

mol = M*V = 0.5*0.100 = 0.05 mol of KMnO4

mass = mol*MW = 0.05*158.034 = 7.9017 g of KMnO4

then, add 7.9017 g of KMnO4 to the solution

mix and stirr

then add the water needed to have a final Volume = 100 ml

the solution should beknow 0.5 M o fKMnO4 and 1 M o fH2SO4