Step 1 : Dissolve one cup of spinach in 300mL of 6M concentrated
Na2CO3 solution.
Na2CO3 (aq) + (COOH)2 (s)
--------> (COONa)2 (aq)+ H2O (l) +
CO2 (g)
In this step the oxalic acid present in the spinach gets soluble in
the form of sodium oxalate.
Step 2 : Separate the water and the other green residue using
separatory funnel and filter paper,
remember that the sodium oxalate is present in water since it is
soluble in it .
Step 3 : Now acidify this solution with strong acid like HCl
HCl (aq) + (COONa)2
(aq) -------> (COOH)2 (aq) + NaCl
(aq)
The oxalic acid (COOH)2 , NaCl are soluble in water we
need to separate them based
on the solubility differences.
Step 4 : Use salts like Ca(OH)2 to precipitate the
oxalic acid, followed by separation using
funnel and evaporation, the oxalic acid can be obtained.
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