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3.156x103 g of C3H6 is mixed with 3.601 x 103 g of NO and produces 2.501...

  1. 3.156x103 g of C3H6 is mixed with 3.601 x 103 g of NO and produces 2.501 x 103 g of C3H3N according to the following equation.

4C3H6(g) + 6NO(g) --> 4C3H3N(g) + 6H2O(g) + N2(g)

  1. Determine the limiting reactant. Use molar ratios to justify your answer.
  2. Determine the theoretical yield of C3H3N in grams
  3. Determine the % yield of C3H3N.
  4. Determine the number of moles of excess reactant that remain once the reaction goes to completion.

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