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A sample of 4.00 g of methane is mixed with 15.0 g of chlorine with the...

A sample of 4.00 g of methane is mixed with 15.0 g of chlorine with the following equation: CH4 (g) + 4 Cl2 (g) = CCl4 (l) + 4HCl (g)
Determine which reactant is the limiting and the calculate the maximum mass of CCl4 that can be formed.
Calculate the theoretical yield.
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Answer #1

CH4 + 4 Cl2 -----------------------> CCl4 + 4 HCl

16g         284g                                 154g

4g            15g

16 g CH4 needs --------------> 284 g Cl2

4 g CH4 needs --------------> x g Cl2

x = 4 x 284 / 16

x = 71 g

we need actually 71 g Cl2 . but we have only 15 g Cl2 . so it is limiting reagent

Cl2 is limiting reagent

product is based on limiting reagnet

284g g Cl2 will give------------------------> 154g CCl4

15 g Cl2 will give ----------------------> y g CCl4

y = 15 x 154 / 284

y = 8.13 g

maximum mass of CCl4 = theoretical yield = 8.13 g

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