A balloon vendor at a street fair is using a tank of helium to fill her balloons. The tank has a volume of 155.0 L and a pressure of 126.0 atm at 23.0 °C. After a while she notices that the valve has not been closed properly. The pressure had dropped to 116.0 atm (The tank is still at 23.0 °C). How many moles has she lost?
we have:
P = 126.0 atm
V = 155.0 L
T = 23.0 oC
= (23.0+273) K
= 296 K
find number of moles using:
P * V = n*R*T
126 atm * 155 L = n * 0.08206 atm.L/mol.K * 296 K
n = 804 mol
This is initial number of moles of gas in tank
we have:
n1 = 804 mol
P1 = 126.0 atm
P2 = 116 atm
we have below equation to be used:
P1/n1 = P2/n2
126.0 atm / 804 mol = 116.0 atm / n2
n2 = 740 mol
this is final number of moles of gas
gas escaped = initial - final
= 804 mol - 740 mol
= 64 mol
Answer: 64 mol
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