Consider the following pathway:
A—> B —> C —>D —> choline (an alcohol found in lipids, whose structure you need to know for the exam.)
Inside growing cells the concentrations of compounds B, C, and D are very low. If you add drug X to growing cells, then compounds B and C accumulate and growth of cells is slower than normal.
In a test tube choline binds to the enzyme that catalyzes the reaction A —> B. Choline probably ______.
binds to the same site as A. |
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binds to the same site as B. |
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is a competitive inhibitor of the enzyme. |
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binds to the enzyme at a different site from A and B. |
Since the concentration of both B and C accumulates this means the reaction rate for path after formation of C is slow, that is Cholin formation is slow and Cholin's use for cell growth has been inhibited by the enzyme.But formation of B and C is not inhibitedn which means Cholin does not bind to the same site as does A or B and also Cholin is not a competitive inhibitor of the enzyme.
So answer is cholin binds to the enzyme at different site from A and B and becomes less available for cell Growth.
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