Question

Which of the following describes the bonding in HNNH?

A) sp orbitals on each nitrogen overlap and form a sigma bond

B) sp orbitals on each nitrogen overlap and form a pi bond

C) sp2 orbitals on each nitrogen overlap and form a sigma bond

D) sp2 orbitals on each nitrogen overlap and form a pi bond

E) p orbitals on each nitrogen overlap and form a sigma bond

Answer 1

The structure of N2H2 is:

here N is SP2 hybridised (because it form 2 sigma bond and has a lone pair. pi bonds are not considered for hybridisation)

So,
SP2 orbital of N will overlap to form sigma bond

so, sigma bond is formed by SP2 orbital of N and s orbital of H

Since pi bonds are not part of hybridisation,
it is formed by 2p orbital of N and 2p orbital of N

only correct statement is:
C) sp2 orbitals on each nitrogen overlap and form a sigma bond

Answer:
C) sp2 orbitals on each nitrogen overlap and form a sigma bond