Question

How to calculate natural log from vapor pressure. I have vapor pressure of 24.47 (atm), temp (K) 293, temp(degree C) 20.0, 1/T(K^-1) 0.00341 and the measured pressure (inches Hg) 25.5

Answer 1

Hi you are talking about Clausius-Clapeyron Equation!

Please visit the following website for more information at

https://www.wikihow.com/Calculate-Vapor-Pressure

https://chem.libretexts.org/Core/Physical_and_Theoretical_Chemistry/Physical_Properties_of_Matter/States_of_Matter/Phase_Transitions/Clausius-Clapeyron_Equation

if you are using ln function then suppose you have

ln(x) = y then x = e^y   OR if you are using logarithm base 10

log₁₀(x) = y then x = 10^y

You have not provided ΔH_vap value i.e The enthalpy of vaporization of the liquid. Otherwise i will calculate it for you.

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