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Calculate the partial pressure (in atm) of CH3OH at equilibrium when 4.84 atm of CH3I and...

Calculate the partial pressure (in atm) of CH3OH at equilibrium when 4.84 atm of CH3I and 4.84 atm of H2O react at 3000 K according to the following chemical equation:

CH3I (g) + H2O (g) ⇌ CH3OH (g) + HI (g) Kp = 7.47×101



Report your answer to three significant figures in scientific notation.

**** i have just one chance !!

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Answer #1

CH3I       + H2O --------------------> CH3OH + HI

4.84    4.84                               0            0

4.84 - x       4.84 - x                               x            x

Kp = x^2 / (4.84 - x)^2

74.7 = x^2 / (4.84 - x)^2

x = 4.34

partial pressure of CH3OH at equilibrium = 4.34 atm

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