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what is the empirical formula of a compound that was found to be 63% Ag ,...

what is the empirical formula of a compound that was found to be 63% Ag , 8.2% N and 28.3% O (by mass) in the blanks , type the subscript that would go with the element. If you find it is a "1" , type "1" in the blank . Do not leave any space empty to receive full credit.

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Answer #1

mass of Ag   = 63 g

moles of Ag = 63 / 108 = 0.583

mass of N = 8.2 g

moles of N = 8.2 / 14 = 0.586

mass of O = 28.3

moles of O = 28.3 / 16 = 1.77

moles ratio = Ag : N : O = 0.583 : 0.586 : 1.77

                                     = 1 ; 1 : 3

empirical formula = AgNO3

note : Ag1 N1 O3 subscript becarefull while entering

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