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For a particular reaction at 188.9 °C, ΔG = 287.40 kJ/mol, and ΔS = 811.42 J/(mol·K)....

For a particular reaction at 188.9 °C, ΔG = 287.40 kJ/mol, and ΔS = 811.42 J/(mol·K). Calculate ΔG for this reaction at 4.1 °C.

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Homework Answers

Answer #1

Given at temperature, T1 = 188.9 DegC = 188.9 + 273 = 461.9 K

G1 = 287.40 kJ/mol = 287400 J/mol

S = 811.42 J/(mol·K)

Applying the relation

G1 = H - T1xS

=> 287400 J/mol =  H - 461.9 K x 811.42 J/(mol·K)

=> H = 662195 J/mol or 662.195 kJ/mol

Now when temperature, T2 = 4.1 DegC = 4.1 + 273 = 277.1 K

Applying the relation

G2 = H - T2xS

=> G2 =  662195 J/mol - 277.1 K x 811.42 J/(mol·K)

=> G2 = 437350 J/mol = 437.35 kJ/mol (answer)

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