Solution:-
Molecular equation:-
2 Na3Po4(aq) + 3 NiCl2(aq) = Ni3(Po4)2(s) + 6 NaCl(aq)
Complete Ionic Equation:
6Na+ (aq) + 2PO4 3- (aq) + 3Ni 2+(aq) + 6Cl- (aq) → 6Na + (aq) + 6Cl-(aq) + Ni3(PO4)2(s)
Net Ionic Equation:
2PO4 3- (aq) + 3Ni 2+ (aq) → Ni3(PO4)2(s)
Formulas of the possible products:
1. Ni3(PO4)2(s) = Nickel(II) phosphate
2. NaCl = Sodium Chloride
Observation and Evidence of Reaction: is a solid precipitate is formed Nickel(II) phosphate
Spectator Ions: Na+ and Cl-
Reacting Ions: PO43- and Ni2+
Yes the reaction occurs and the type of reaction is "Double Replacement reaction".
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