Question

What is the chemical equation for reducing Tetraamine copper(II) culfate with magnesium? The lab talks about...

What is the chemical equation for reducing Tetraamine copper(II) culfate with magnesium? The lab talks about adding HCl to dissolve the excess magnesium solids and see the hydrogen gas being released the product of this equation is supposed to give us our solid copper back?

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Answer #1

Tetraamine copper(II) sulfate is Cu(NH3)4SO4 (tetramine means it has 4 amine NH3 group and Cu in +2 state, Sulfate for SO4 group) and when it reacts with magnesium Mg we have the following reaction -

Cu(NH3)4SO4 + Mg -> Cu + MgSO4 + 4NH3

solid Cu (copper) gets deposited at the bottom of the beaker

Here. if we take Mg in excess we need to dissolve the excess by adding HCl so, the following reaction will take place -

Mg + 2HCl -> MgCl2 + H2

Releases H2 gas.

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