Complete and balanceNaCl(aq)+Hg2(C2H3O2)2(aq)
My answer 2NaCl(aq) +Hg2(C2H3O2)2(aq) --2HgCl(s) + 2NaC2H3O2 (aq) is wrong and I don't understand why. They said "Check the grouping of your atoms and the solubility of your products. Mercury exists as the diatomic cation Hg2+2." Can you explain what I am doing wrong?
Mercury (I) is a dimer consisting of a mercury (II) ion and a neutral mercury atom. There are no individual mercury (I) ions. This is why there is no HgCl, only Hg2Cl2. It is said that mercury (I) (Hg22+) disproportionates to form mercury (II) and mercury metal as if this were a redox reaction and the mercury was changing oxidation state. But instead of a redox reaction to make Hg and Hg(II) from Hg22+, it simply decomposes. There is no electron transfer because the Hg22+ ion exists as an atom of mercury bonded to a Hg2+ ion, as in Hg-Hg2+.
Hence the balanced chemical reaction is
2NaCl (aq) +Hg2(C2H3O2)2(aq) Hg2Cl2(s) + 2NaC2H3O2 (aq)
Get Answers For Free
Most questions answered within 1 hours.