Question

Calculate ∆E and the work done in joules when 50.0 g of tin (MM = 118.7...

Calculate ∆E and the work done in joules when 50.0 g of tin (MM = 118.7 g/mol) dissolves in excess acid producing 10.3 L of H2 (MM = 2.016 g/mol) gas at 1.00 atm and 25°C. The initial volume of gas is 0 L.

Sn (s) + 2H+ (aq) → Sn2+ (aq) + H2 (g) ∆Hrxn = -137 kJ

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Answer #1
  • It is a good approximation to neglect the volumes of solids and liquids in comparison to those of gases.
  • I have treated the ∆Hrxn given here to be a molar property ie for 1 mol reaction.

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