Under certain conditions, the equilibrium constant of the reaction below is Kc=1.7×10−3 . If the reaction begins with a concentration of 0.0546 M for each of SbCl3 and Cl2 and a concentration of 0 M for SbCl5 , what is the equilibrium concentration (in molarity) of Cl2 ?
SbCl5(g)↽−−⇀SbCl3(g)+Cl2(g)
round your answer to the nearest ten-thousandth
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